How about the situation that the opamp can be used like a comperator for binary signals? Where high is equivalent to Vdd and occasional is equivalent to ground and also the threshold is Vdd/2 and also the common mode input range is 1/6*Vcc to fiveOr6*Vcc. The Vc is going to be somewhere in the plethora of 1/4*Vdd to threeOr4*Vdd and therefore within range, and can it operate correctly? The input current does exceed the most popular mode input range. Henk Apr 2 '14 at 9:08
@Henk, you shouldn't make use of an op-amp by using it's common mode input outdoors the required range. Most likely the only effect will disappear bandwidth, or possibly it'll cause large currents to circulate within the input pins, disturbing all of those other circuit. Some op-amps also provide issues once the common mode input is big (greater than a couple of mV). Choose another op-amp for the application or, better still, make use of a part designed to become a comparator and never an op-amp. The Photon Apr 2 '14 at 16:21
Essentially, the word common mode signifies that the signal in the two input terminals of the differential amplifier is similar both in magnitude and phase.
When signals V1 and V2 are applied as input we are able to spilt them into a mix of common mode and differential mode signals within the following manner
V1 = (V1 + V2)/2 + (V1 - V2)/2
thus, (V1 + V2)/2 may be the common part and (V1 - V2)/2 may be the differential area of the signal.
Among the signals that's always used in the most popular mode may be the Electricity Bias. It is primarily the common mode signal the Input Common Mode Range is connected with. Therefore, the ICMR is the plethora of input Electricity (or Common Mode) current range that the circuit is within saturation (or as intended as).
In the previous computation when we consider V1 and V2 to possess both ac and electricity components, for example (V0 +/- A crime wt) then V0 will be the Electricity common mode signal put on the amplifier.
clarified 12 , 31 '14 at 6:59